Angle between two vectors vec A = 2hat{i} + hat{j} - hat{k} and vec B = hat{i} - hat{k}

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3-1.Vectors

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Find the angle between two vectors $\vec A = 2\hat i + \hat j - \hat k$ and $\vec B = \hat i - \hat k$ ....... $^o$

A

$40$

B

$30$

C

$20$

D

$10$

Solution

$\cos \,\theta = \frac{{\vec A.\vec B}}{{AB}} = \frac{{2 + 1}}{{\sqrt 6 + \sqrt 2 }} = \frac{3}{{\sqrt 6 \sqrt 2 }} = \frac{{\sqrt 3 }}{2}$

$\therefore$ $\theta = 30^o$

Standard 11

Physics

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